solve x square minus root 3 + 1 X + root 3 is equal to zero by the method of completing square
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We have,
x 2 −( 3 +1)x+ 3 =0
⇒x 2 −(3 +1)x=− 3
⇒x 2 −2( 23 +1 )x+( 23 +1 ) 2=− 3 +( 23 +1) 2
⇒(x− 23 +1 ) 2 = 4-4 3 +( 3 +1) 2
⇒(x− 23 +1 )2 =( 23−1 ) 2
⇒x− 23 +1 =± 23 −1
⇒x= 23 +1 ± 23 −1
⇒x= 3 ,1Hence, the roots are 3 and 1.
hope it helps
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