Question

SOLVE x to tge power root x is equal to in root x to the power x.

Answer 1

HEY.......
HERE IS U R ANSWER
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${x}^{ \sqrt{x} } = \sqrt{ {x}^{x} } \\ square \: both \: side \\ {x}^{2 \sqrt{x} } = {x}^{x} \\ 2 \sqrt{x} = x \\ square \: both \: side \\ 4x = {x}^{2} \\ \\ x {}^{2} - 4x = 0 \\ x(x - 4) = 0 \\ x = 0 \\ x = 4 \\ andx \: = 1 \: as \: it \: satisy \: it$

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Answer 2

${x}^{ \sqrt{x} } = { \sqrt{x} }^{x}$
${x}^{ \sqrt{x} } = {x}^{ \frac{x}{2} }$
$\sqrt{x} = \frac{x}{2}$
$x = \frac{ {x}^{2} }{4}$
${x}^{2} - 4x = 0$
$x(x - 4) = 0$
$x = 4$