Question

solve :x-x-2/7+36=9X+7/2

Answer 1

So ATQ-
x-x-2/7+36=9x+7/2
-2/7+36=9x+7/2
9x+36=7/2+2/7
9x+36=(49+4)/7
9x+36=53/7
9x=53/7-36
9x=(53-252)/7
9x=199/7
x=199/7*1/9
x=199/63(answer)
Hope it helps you!!!
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Answer 2

Answer:

$\; \star \; {\underline{\underline{\textsf{\textbf{ \; Given \; :- }}}}}$

${\; \; \longmapsto \; \sf { \dfrac{ 9x + 7 }{2} - \bigg[ x - \dfrac{x - 2}{7} \bigg] = 36 } }]$

$\begin{gathered} \\ \\ \end{gathered}$

$\; \star \; {\underline{\underline{\textsf{\textbf{ \; To \; find \; :- }}}}}$

• ⟼ Value of x

$\begin{gathered} \\ \\ \qquad{\rule{200pt}{2pt}} \end{gathered}$

$\; \star \; {\underline{\underline{\textsf{\textbf{ \; SolutioN \; :- }}}}}$

$\begin{gathered} \; \; {\longmapsto{\qquad{\sf{ \dfrac{ 9x + 7 }{2} - \bigg[ x - \dfrac{x - 2}{7} \bigg] = 36 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ \dfrac{ 9x + 7 }{2} - \bigg[ \dfrac{(7x - x) - 2}{7} \bigg] = 36 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ \dfrac{ 9x + 7 }{2} - \bigg[ \dfrac{6x - 2}{7} \bigg] = 36 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ \dfrac{ 63x + 49 - 12x - 4}{14} = 36 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ \dfrac{ (63x - 12x) + (49 - 4)}{14} = 36 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ \dfrac{ 51x + 45 }{14} = 36 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 51x + 45 = 36(14) }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 51x + 45 = 504 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 51x = 504 - 45 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 51x = 459 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ x = \dfrac{459}{51} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ x = \cancel\dfrac{459}{51} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\pmb{\underline{\boxed{\purple{\frak{ x = 9 }}}}}}}} \; \bigstar \\ \\ \\ \ \end{gathered}$

$\begin{gathered} \\ \\ \end{gathered}$

$\qquad \; \therefore \;$x = 09

$\begin{gathered} \\ {\underline{\rule{300pt}{9pt}}} \end{gathered}$