solve :
X+Y=18; Y+Z=12; Z+X=16
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Answered by
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Given that
X + Y = 18 ; Y + Z = 12 ; Z + X = 16
Solution
X + Y = 18
=> X = 18 - Y ---------(i)
Y + Z = 12
=> Z = 12 - Y --------(ii)
From equation (i) and (ii)
Z + X = 16
=> 12 - Y + 18 - Y = 16
=> 30 - 2Y = 16
=> - 2Y = 16 - 30
=> - 2Y = - 14
=> Y = -14/-2
=> Y = 7
Therefore ,
X = 18 - Y
= 18 - 7
= 11
Z = 12 - Y
= 12 - 7
= 5
Given that
X + Y = 18 ; Y + Z = 12 ; Z + X = 16
Solution
X + Y = 18
=> X = 18 - Y ---------(i)
Y + Z = 12
=> Z = 12 - Y --------(ii)
From equation (i) and (ii)
Z + X = 16
=> 12 - Y + 18 - Y = 16
=> 30 - 2Y = 16
=> - 2Y = 16 - 30
=> - 2Y = - 14
=> Y = -14/-2
=> Y = 7
Therefore ,
X = 18 - Y
= 18 - 7
= 11
Z = 12 - Y
= 12 - 7
= 5
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