Solve x – y = 28 and x – 3y = 0 and hence, find the value of ‘m’ for which y = mx + 5
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Answer:given x−y=28,x−3y=0
⇒28+y=3y
⇒2y=28,y=14
therefore x=42
now substituting these values in y=mx+5
we get 14=42m+5,m=429
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