Question

Solve x +y=3;5x+ 2y = 12

Answer 1

Answer:

Value of x and y are 2 and 1 respectively

Step-by-step explanation:

We Have :-

x + y = 3

5x + 2y = 12

To Find :-

x and y

Solution :-

x + y = 3 ------------------ ( i )

5x + 2y = 12 ------------- ( ii )

[ ( i ) * 5 ] - [ ( ii ) * 1 ]

5x  + 5y =  15

-5x - 2y  = -12

__________

0x + 3y = 3

y = 3 / 3

y = 1

Putting in ( i )

x + 1 = 3

x = 3 - 1

x = 2

x + y

2 + 1

3

x - y

2 - 1

1

Value of x and y are 2 and 1 respectively

Answer 2

Answer:

$\small \underline\textbf{X=1}$

$\small\underline\textbf{Y=1 }$

$\sf\red{Given}\begin{cases}\bf\red{X+Y=3} \\ \bf\red{5x+2y=12}\end{cases}$

$\large\underline\textsf{ To Find}$

$\small\bf{ The\: value\: of \:X \:and\: Y}$

$\huge\underline\textsf{Explantion:- }$

$\rightarrow\bf x + y = 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1 \: question$

$\rightarrow\bf5x + 2y = 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \: question$

$\rule{300}{2}$

$\rightarrow\bf(1) \times 5 - (2) \times 1$

$\rightarrow\bf5x + 5y = 15 \\ \rightarrow\bf - 5x - 2y = 12$

$\rightarrow\bf0x \times 3y = 3 \\ \bf\rightarrow y = \frac{\cancel3}{\cancel3}$

$\rightarrow\bf Y = 1$

$\rule{300}{2}$

$\rightarrow\bf x + 1 = 3 \\ \rightarrow\bf x = 3 - 1 \\ \rightarrow\bf x = 2$

$\rightarrow\bf{X+Y } \\ \rightarrow\bf{2+1} \\ \rightarrow\bf{3}$

$\rightarrow\bf{X-Y } \\ \rightarrow\bf{2-1} \\ \rightarrow\bf{1}$

$\rule{300}{2}$

$\small \underline\textbf{X=1}$

$\small\underline\textbf{Y=1 }$