Math, asked by SamuelCoursing, 1 year ago

Solve : x²+15x-1080..........


MrThakur14Dec2002: in which class u study dude

Answers

Answered by MrThakur14Dec2002
4
Solution ----------

 {x}^{2}  + 15x - 1080 = 0

a = 1 ; b = 15; c = -1080

d =  {b}^{2}  - 4ac \\  \\  \\ d \:  =  \: {15}^{2}  - 4 \times 1 \times  (- 1080)

D = 225 + 4320

D = 4545.


x =   \frac{ - b +   \sqrt{d} }{2a}  \:  \:  \:  \:  \: or \:   \frac{ - b -  \sqrt{d} }{2a}


x =  \frac{ - 15 + 3 \sqrt{505} }{2}  \:  \:  \:  \: or \:  \frac{ - 15 -  3\sqrt{505} }{2}
 \\  \\  \\  \\  \\  \\ hope \: this \: will \: help \: you............ \:  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\ be \: brainly..........


MrThakur14Dec2002: have u any doubt then ask me.
asit183: hiiii
Answered by Anonymous
9

\textsf{Given :}\\\\\mathsf{x^2+15x-1080=0}


\textsf{Comparing with }\mathsf{ax^2+bx+c}\textsf{ we get :}


\mathsf{a=1}\\\mathsf{b=15}\\\mathsf{c=-1080}


\mathsf{Discriminant\:\: \triangle=b^2-4ac}\\\mathsf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=15^2-4.1.(-1080)}\\\mathsf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=225+4320}\\\mathsf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=4545}


\mathsf{Apply\:the\:quadratic\:formula:\:x=\frac{-b\pm\sqrt{\triangle}}{2a}}\\\mathsf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{-15\pm\sqrt{4545}}{2\times1}}\\\mathsf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{-15\pm3\sqrt{505}}{2}}


\textsf{\huge{\underline{\underline{\underline{\underline{\underline{\underline{ANSWER}}}}}}}}}}


\underline{\mathsf{The\:roots\:of\:the\:equation\:are\:either\:}}\\\\\frac{-15+3\sqrt{505}}{2}\\\\\mathsf{or}\\\\\frac{-15-3\sqrt{505}}{2}


\textsf{Hope it helps you bro :-) }


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