Question

solve.
x2 - 2(a + 2)x + (a + 1)(a + 3) = 0​

Answer 1

Answer:

ANSWER

Given x

2

+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)

x=

2a

−b±

b

2

−4ac

=

2(1)

−1±

1

2

−4{(a+2)(a+1)}

=

2

−1±

1−4{−(a

2

+3a+2)

x=

2

−1±

1+4a

2

+12a+8

=

2

−1±

4a

2

+12a+9

=

2

−1±

(2a+3)

2

=

2

−1±(2a+3)

∴x=

2

−1+2a+3

and x=

2

−1−2a−3

∴x=

2

2a+2

and x=

2

−2a−4

x=a+1x=−(a+2)

∴ The roots of x

2

+x−(a+2)(a+1)=0 are (a+1) and −(a+2)

Answer 2

Answer:

x=a+1, x=a+1

Step-by-step explanation:

x2-2(a+2)x+(a+1)(a+3)=0

x2-(a+1)x-(a+3)x+(a+1)(a+3)=0

x(x-a-1)-(a+3)(x-a-3)=0

(x-a-1)(x-a-3)

x=a+1 , x=a+3

hope this will help you