Question

Solve x²-2x-5=0 for a positive root by iteration method.

Answer 1

-(-2)+√(-2)^2-4*1*(-5)/2*1

=2+√(-2)^2+4*1*5/2*1

2+√(-2)^2+4*1*5

=2+√24

=2+√24/2

=2+2√6/2

2(1+√6)/2

1+√6

(-2)-√(-2)^2-4*1*(-5)

=2√(-2)^2+4*1*5/2*1

=2-√4/2*1

=2-2√6/2

1-√6

x= 1 + √6, x= 1-√6