Question

solve x²-4√2x+6=0 by factorization method​

Answer 1

Step-by-step explanation:

x^2-4√2x +6=0

→x^2-3√2x -√2x +6=0

→x(x-3√2)-√2(x-3√2)= 0

→(x-√2)(x-3√2)= 0

→x-√2= 0 or , x-3√2=0

→x=√2 or , x=3√2

Answer 2

x²-4√2x+6 =0

x²-3√2x-√2x+6 =0

x(x-3√2)-√2(x-3√2) =0

(x-√2)(x-3√2) = 0

If,

x-√2 = 0

x = √2

or,

x-3√2=0

x= 3√2