solve x2 - 4x - 221 with the method first answer will be marked as brainliest
Answers
Answered by
3
Hey Friend ☺
x^2 - 4x - 221 = 0
》x^2 - 17x + 13x - 221 = 0
》x ( x - 17 ) + 13 ( x - 17 ) = 0
》( x - 17 )( x + 13 ) = 0
x - 17 = 0. or. x + 13 = 0
x = 17. or. x = - 13
Hope it helps you ..!!
✌
x^2 - 4x - 221 = 0
》x^2 - 17x + 13x - 221 = 0
》x ( x - 17 ) + 13 ( x - 17 ) = 0
》( x - 17 )( x + 13 ) = 0
x - 17 = 0. or. x + 13 = 0
x = 17. or. x = - 13
Hope it helps you ..!!
✌
sharansss114:
thanks
welcome :-)
Answered by
2
x2-17x+13x-221
x(x-17)+13(x-17)
x+13;x-17
so zeros are
x=-13 and x=17
x(x-17)+13(x-17)
x+13;x-17
so zeros are
x=-13 and x=17
Similar questions