Question

solve x²+4x-5=0 by the method of completing square​

Answer 1

Answer:

x² - 4x - 5 = 0

x² -4x = 5

x² - 2(x)(2) = 5

adding (2²) on both sides,

x² -2(x)(2) + 2² = 5 + 4

on comparing L.H.S to identity:

a² + 2ab + b² = (a + b)²

(x - 2)² = 9

x - 2 = ±√9 = ±3

x = ±3 + 2

case 1: x = 3 + 2 = 5

case 2: x = -3 + 2 = -1

Answer 2

Answer:

x²+4x-5=0

x²+4x+4-9=0

(x+2)²-9=0

(x+2)²=9

(x+2)²=3²

(x+2)=3

x=3-2

x=1

or

(x+2)=-3

x=-3-2

x=-5

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