Math, asked by shwetabajpai477, 3 days ago

Solve: x2 + 8x - 48 = 0
By Completing the square.
x2 + 8x - 48 = 0
x2 + 8x + - 16 - 48 = 0
... 2-64 = 0
.. x + 4 = 8 or x + 4 =
x= 4 or x = ...​

Answers

Answered by yashdhanik1122
1

Answer:

x

2

+8x−48=0

⇒x

2

+8x+16−64=0

⇒x

2

+2.x.4+4

2

−64=0

⇒(x+4)

2

−(8)

2

=0

⇒(x+4+8)(x+4−8)=0

⇒(x+12)(x−4)=0

∴x=−12,x=4

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