Question

Solve [x²D²+XD +1] y = sin(logx) solve using Euler theaorem
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Answer 1

Step-by-step explanation:

Regroup terms.

y(x^2D^2 + XD + 1) sin(logx)

Divide both sides by x^2D^2 + XD +1.

y= sin(logx) / x^2D^2 + XD + 1

Answer 2

Step-by-step explanation:

(x^2D^2-xD+1)y=sin(logx)