Question

Solve x³-3x²+2x and help me know the correct answer

Answer 1

         

$x^3-3x^2+2x \\ \\ \Rightarrow\ x(x^2-3x+2) \\ \\ \Rightarrow\ x(x^2-x-2x+2) \\ \\ \Rightarrow\ x(x(x-1)-2(x-1)) \\ \\ \Rightarrow\ x(x-1)(x-2) \\ \\ \\ \therefore\ x^3-3x^2+2x=x(x-1)(x-2) \\ \\ \\ \therefore\ x=\bold{0}\ \ \ ; \ \ \ x=\bold{1}\ \ \ ; \ \ \ x=\bold{2}$

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Answer 2

Answer:

>> x^3 - 3x^2 - x + 3   + 3 x - 3

>> x^2 * (x - 3) - 1  * (x - 3)    + 3 x - 3

>> (x^2 - 1) * (x - 3)   + 3 x - 3

>> (x - 1)(x + 1) * (x - 3)   + 3 (x - 1)

>>  (x - 1)[(x + 1) * (x - 3)   + 3]

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