solve xsquare+7x-6=0 by completing square method
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Answered by
44
Given x^2 + 7x - 6 = 0
x^2 - 7x = 6
Take the coefficient of x and divide by 2. The formula is (b/2)^2 = (7/2)^2 = 49/4.
Add 49/4 to both sides of equation
x^2 - 7x + (49/4) = 6 + 49/4
x^2 - 7x + (49/4) = 73/4
(x - 7/2)^2 = 73/4
x - 7/2 = root 73/4
x = 7/2 + root 73/4 and x = 7/2 - root 73/4
(or)
x = 7/2 + root 73/2 and x = 7/2 - root 73/2.
Hope this helps!
x^2 - 7x = 6
Take the coefficient of x and divide by 2. The formula is (b/2)^2 = (7/2)^2 = 49/4.
Add 49/4 to both sides of equation
x^2 - 7x + (49/4) = 6 + 49/4
x^2 - 7x + (49/4) = 73/4
(x - 7/2)^2 = 73/4
x - 7/2 = root 73/4
x = 7/2 + root 73/4 and x = 7/2 - root 73/4
(or)
x = 7/2 + root 73/2 and x = 7/2 - root 73/2.
Hope this helps!
mysticd:
It is not completing square method sir
Okk..Will try..
Thanks Mysticd.I have corrected my answer
Answered by
52
Hey there!!!
Here is your answer...
HOPE IT HELPS☺️
Here in my second line I had written wrong
it should be x2+2x ×(7/2)+ (7/2)2.
Here is your answer...
HOPE IT HELPS☺️
Here in my second line I had written wrong
it should be x2+2x ×(7/2)+ (7/2)2.
Attachments:
Plz , check again
x² + 7x + ( 7/2 )² this line wrong, plz edit
x² + 2 × x × ( 7/2 ) + ( 7/2 )²
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