The ratio of the area of two squares,one having its diagonal double that of the other is
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Answered by
83
area of one square = A1, diagonal = d
area of second square = A2, diagonal = 2d
ratio= A1/A2 = (d²/2)/[(2d)²/2]
= (1/2)/[4/2]
=1/4
area of second square = A2, diagonal = 2d
ratio= A1/A2 = (d²/2)/[(2d)²/2]
= (1/2)/[4/2]
=1/4
mysticd:
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Answered by
74
let diagonals be 2d and d.
then, A1/A2=1÷2 (2d)^2/1÷2d^2
A1/A2=4d^2/d^2
A1/A2=4/1
A1:A2=4:1
the ratio is 4:1
then, A1/A2=1÷2 (2d)^2/1÷2d^2
A1/A2=4d^2/d^2
A1/A2=4/1
A1:A2=4:1
the ratio is 4:1
hope it helps
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