Solve:
y+2÷4-Y-3÷3 =1÷2
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3y−1
3y−1
3y−1 −
3y−1 − 4
3y−1 − 4y−2
3y−1 − 4y−2
3y−1 − 4y−2 =1
3y−1 − 4y−2 =112
3y−1 − 4y−2 =1124y−4−3y+6
3y−1 − 4y−2 =1124y−4−3y+6
3y−1 − 4y−2 =1124y−4−3y+6 =1
3y−1 − 4y−2 =1124y−4−3y+6 =1⇒y+2=12
3y−1 − 4y−2 =1124y−4−3y+6 =1⇒y+2=12⇒y=10.
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