Question

Solve : y + 2√y +1 = 0

Answer 1

Step-by-step explanation:

y+2√y+1=0

we can write

(√y)^2+2√y+1=0

(√y)^2+√y+√y+1=0

√y(√y+1)+1(√y+1)=0

(√y+1)(√y+1)=0

√y=-1

y=√-1

y had imaginary and unequal roots