Question

Solve.y-2✓y +1=0......…...........

Answer 1

hey mate here is your answer ✌♥✌

y-2√y+1=0

so let√y=X

so

x²-2x+1=0

so by splitting the middle term method

x²-x-x+1=0

X(x-1)-1(x-1)=0

(x-1)(x-1)=0

so X={1,1}

now X=√y

so √y=1

squaring on both sides

y=1

hope it will be helpful to you ✔✔

mark me brainliest ✌✌✌✌

Answer 2

y -2√y + 1 = 0
y + 1 = 2√y
Squaring both sides.
${y}^{2} + 1 + 2y = 4y$
${y}^{2} - 2y + 1 = 0$
For finding it's roots :
D = b^2 - 4ac
= (-2)^2 - 4x1x1
= 4 - 4
= 0
Hence there will be two equal roots.
Root = - b / 2a
= -(-2)/2x1
= 1.

Answer is y = 1.