Math, asked by sreenudobbala, 1 year ago

solve y^"+4y=cosxcos3x

Answers

Answered by Anonymous

1

Answer:

equations: (i) y"-4y = 0 (ii) y"-y'-2y = 0 (iii) ... 4y = cosx cos3x (v) y"-4y = x2 (vi) y"- 2y' + 3y = cosx + x2 (vii) y"-4y' + 4y ...

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