Math, asked by shaikfayaz198pcdgtu, 1 year ago

solve y11+2ky1+(k2+4)y=0


shaikfayaz198pcdgtu: 2^ky^1 hai
shaikfayaz198pcdgtu: y^11+2^ky^1+(k^2+4)y=0
shaikfayaz198pcdgtu: waiting for ur ans. thank u
shaikfayaz198pcdgtu: or 2^k^y1 is this ok

Answers

Answered by sangsthita32
1

y11+2ky1+(k2+4)y=0
y11+2ky1+k2y+4y=0
15y+4ky=0
4ky=-15y
4k=-15y/y
=-15
k =-15/4
-3.75


shaikfayaz198pcdgtu: y^11+2^ky^1+(k^2+4)y=0
shaikfayaz198pcdgtu: this is the question ji
shaikfayaz198pcdgtu: thank u
sangsthita32: did i write the wrong answr?
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