solve y11+2ky1+(k2+4)y=0
shaikfayaz198pcdgtu:
2^ky^1 hai
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y11+2ky1+(k2+4)y=0
y11+2ky1+k2y+4y=0
15y+4ky=0
4ky=-15y
4k=-15y/y
=-15
k =-15/4
-3.75
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