Solved Problem 5
A bag contains 8 tickets which are marked with the numbers 1, 2, 3... 8.
Find the probability that a ticket drawn at random from the bag is marked
with (i) an even number (ii) a multiple of 3.
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On the first draw there are 25 possible results. 13 of them are odd, so the chance of success on that draw are 13/25.
If successful the first time, there are now 24 numbers in the box and 12 of them are odd. The chances of success on this draw is 12/24 = 1/2.
The odds of getting 2 odds and thus an odd product is (13/25)(1/2) = 13/50.
The probability of not getting 2 odd numbers and thus getting an even product is 1 - 13/50 = 37/50 = 74/100 = 74%
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