English, asked by annacatherineshelvi, 5 months ago

SOLVED PROBLEMS
10. Calculate the number of atoms present in 3.0586 L of helium at 298 K and 1.5
atm. [He = 4]

Answers

Answered by kbala4704

0

Answer:

he 4

Explanation:

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Answered by durgacsshaji

2

Answer:

1.129×10^23

Explanation:

No. of He atoms=((V0 in L) ÷(22.414)×(6.022×10^23)) =1.129×10^23

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