solved question of limit
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Hi !!!!
Put x = infinity we get. infinity / infinity
So, by Applying L-hospitals rule ( differentiation nr and dn separately till u come out from infinity/infinity.)
Lt. (9x² +2x )/ (2x -1 )
x->inf.
Lt (18x +2 ) / 2
x->inf
now put x = inf.
we get. infinity.
2nd Method :-
x ³ { 3 + (1 / x ) - (1/ x³)}. /. x ² { 1 -( 1 / x ) + (7 / x²)}
put x = inf.
we get
infinity
Put x = infinity we get. infinity / infinity
So, by Applying L-hospitals rule ( differentiation nr and dn separately till u come out from infinity/infinity.)
Lt. (9x² +2x )/ (2x -1 )
x->inf.
Lt (18x +2 ) / 2
x->inf
now put x = inf.
we get. infinity.
2nd Method :-
x ³ { 3 + (1 / x ) - (1/ x³)}. /. x ² { 1 -( 1 / x ) + (7 / x²)}
put x = inf.
we get
infinity
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