Question

the normality of 10 volume of H2O2 is nearly
1) 2.1
2) 3.4
3) 1.7
4) 5.1
plzz explain it ............

Answer 1

Answer:1.7

Explanation:

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Answer 2

Given:

Volume of $H_2O_2$ = 10

To find:

Normality of the given solution

Formula to be used:

Normality = Molarity × n factor

Calculation:

The chemical equation involved in the reaction is:

$2H_2O_2\rightarrow H_2O+O_2$

From the above equation it is clear that 2 moles of $H_2O_2$ gives 1 mole of $O_2$.

10 Volume of $H_2O_2$ yields 10 liter of $O_2$  and for 1 liter of

∴ Number of moles in 1 L of $H_2O_2$ = Moles of

When these values are substituted in the normality formula, it gives:

Normality = Molarity × n factor

Normality = 0.814 × 2 = 1.63 N

Conclusion:

The normality of 10 volume of $H_2O_2$ is nearly 1.63 N. Thus option 3 is correct

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