solved question of mathematics is question 5
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A.p. for 5th term=a+(5-1)d=>a+4d=11----(i)
A.p. for 9th term =a+(9-1)d=>a+8d=7----(ii)
Subtracting equ. 1 from equ. 2
We get,
a+8d=7
-a-4d=-11
-------------
4d=-4
d=-1
-------------
Putting d in equ.1
a+4d=11
a+4(-1)=11
a-4=11
a=11+4
a=15
So, 16th term is
a+(16-1)d
15+15(-1)
15-15=0
0 is 16th term
A.p. for 9th term =a+(9-1)d=>a+8d=7----(ii)
Subtracting equ. 1 from equ. 2
We get,
a+8d=7
-a-4d=-11
-------------
4d=-4
d=-1
-------------
Putting d in equ.1
a+4d=11
a+4(-1)=11
a-4=11
a=11+4
a=15
So, 16th term is
a+(16-1)d
15+15(-1)
15-15=0
0 is 16th term
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