Question

* Solved the following linear programming problem graphically:
Maximize Z = 60.x + 15y
Subject to constraints
x + y = 50
3.x + y < 90
X, y 20​

Answer 1

Step-by-step explanation:

Consider line x + y = 50

Put x = 0, y = 50, (0,50)

Put y = 0, x = 50 (50,0)

Consider the line 3x + y =- 90

Put x = 0, y = 90 (0,90)

Put y = 0, x = 30 (30,0)

Plot the above lines on the graph we get OABC is the solution region

corner point Z=60x+15y

O(0,0). 0

A(0,50). 750

B(20,30). 1,650

C(30,0). 1,800 ---^max

> is maximum at C(30,0)

Zmax=1800

follow

i hope ki