Question

solved this 6y²-35y+50=0

Answer 1

Given Equation is 6y^2 - 35y + 50 = 0

6y^2 - 20y - 15y + 50 

2y(3y - 10) - 5(3y - 10)

(2y - 5)(3y - 10) = 0

y = 5/2,y = 10/3.


Hope this helps!

Answer 2

HELLO DEAR,

$6 {y}^{2} - 35y + 50 = 0 \\ = > 6 {y}^{2} - 20y - 15y + 50 = 0 \\ = > 2y(3y - 10) - 5(3y - 10) \\ = > (2y - 5)(3y - 10) \\ = > y = \frac{5}{2} \: \: \: \: \\ \: \: \: \: \: \: \: and \: \: \: \: y = \frac{10}{3}$
I HOPE ITS HELP YOU DEAR,
THANKS