Question

Solving equation (2x+3)(2x+5)(x-1)(x-2)=30 the roots available are
(a) 0 (1)/(2) -(11)/(4) (9)/(4)
(b) 0 -(1)/(2) (-1+-sqrt(105))/(4)
(c) 0 -(1)/(2) -(11)/(4) -(9)/(4)
(d) None​

Answer 1

if LHS=RHS you should,

2x+3+2x+5+x-1+x-2=30

4x+8+x-1+x-2=30

6x+8-3=30

6x+5=30

6x=30-5

6x=25

x=25/6

x=4