Math, asked by hammakaur, 7 months ago

solving equation that has variables on the both sides 8(x-3)(6-2x)=(x+2)-5(5-x)​

Answers

Answered by NewGeneEinstein
6

Step-by-step explanation:

8 (x-3)(6-2x)=(x+2)-5(5-x)

\implies{8x-24×(6-2x)=(x+2)-25+5x}

\implies{8x(6-2x)-24(6-2x)=-25(x+2)+5x(x+2)}

\implies{48x-{16x}^{2}-144+48x=-25x-50+{5x}^{2}+10x}

\implies{{16x}^{2}+96x-144={5x}^{2}-15x-50}

\implies{{16x}^{2}-{5x}^{2}+96x+15x=-50+144}

\implies{{11x}^{2}+111x=94}

\implies{\boxed{{11x}^{2}+111x-94=0}}

Hence verified

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