Question

solving equtation x²- (a+b) x+ab=0 find the value of x ?​

Answer 1

Step-by-step explanation:

putting

a= 1

b= -(a+b) = b-a

c= ab

in

${b}^{2} - 4ac$

(b-a )^2 - 4× 1×ab

b^2 + a^2 -2ab - 4ab

b^2 + a^ 2 -6ab

put this in the quadratic equation

HOPE IT HELPS :)

Answer 2

Step-by-step explanation:

x²-(a+b)x + ab = 0

x²-ax - bx + ab = 0

x(x-a) - b(x-a) = 0

(x-a)(x-b) = 0

Now, separating these both

1. x-a =0

x = a

2. x-b =0

x = b