Math, asked by ramk8902, 4 months ago

solving factorization method 3x^2-x-10=0​

Answers

Answered by suvansethy
7

Answer:

3x^2-x-10=0 \\3x^2-6x+5x-10 \\3x(x-2)+5(x-2)\\(3x+5)(x-2)

Step-by-step explanation:

Answered by aloksingh17801980
0

Answer:

Answer:

\begin{gathered}3x^2-x-10=0 \\3x^2-6x+5x-10 \\3x(x-2)+5(x-2)\\(3x+5)(x-2)\end{gathered}

3x

2

−x−10=0

3x

2

−6x+5x−10

3x(x−2)+5(x−2)

(3x+5)(x−2)

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