solving quadratic equation x2+8x=-15,find third term but answer should be 16
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x^2 + 8x + 15 = 0
=> x^2 + 5x + 3x + 15 = 0
=> x(x+5) + 3(x+5) = 0
=> (x+3)(x+5) = 0
Hope it helps.
=> x^2 + 5x + 3x + 15 = 0
=> x(x+5) + 3(x+5) = 0
=> (x+3)(x+5) = 0
Hope it helps.
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