Some chocolates are distributed equally among some students. Had the number of
students been 5 less, then each would get 6 chocolates and had the number of students
be 3 more, then each would get 3 chocolates. Find the number of chocolates and the
number of students.
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Answer:
There are 13 students and 48 chocolates
Step-by-step explanation:
No. of students = s
No. of chocolates = c
1) s-5 = c/6
s = (c/6)+5
2) s+3 = c/3
s+3 = c/3
s = (c/3)-3 s = (c/6)+5
(c/3)-3 = (c/6)+5
2c-18 = c+30
c-18 = 30
c = 48
substitute c = 48 into equation 2
s+3 = 48/3
s = 16-3
s = 13
so there are 13 students and 48 chocolates
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