Some copper is mixed with gold during preparation of an ornament. One such ornament weighs 50 g wt in air and 46 g wt in water. Specific gravity of copper is 10, while that of gold is 20. The amount of gold in gm in the ornament will be
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Mass of the ornament = 50 gm
Volume of the ornament = (50 - 46) = 4 cm^3
Let V1 be the volume of gold and V2 be the volume of copper in the ornament
v1 *d1 + v2 d2 = 50 gm
20 v1 + 10 v2 = 50 gm
v1 + v2 = 4 cm^3
v1 = 1 cm^3 and mass of gold = 20 gm
v2 = 3 cm^3 and mass of copper = 30 gm
Volume of the ornament = (50 - 46) = 4 cm^3
Let V1 be the volume of gold and V2 be the volume of copper in the ornament
v1 *d1 + v2 d2 = 50 gm
20 v1 + 10 v2 = 50 gm
v1 + v2 = 4 cm^3
v1 = 1 cm^3 and mass of gold = 20 gm
v2 = 3 cm^3 and mass of copper = 30 gm
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