Some math questions.
1. What is the value of x?
1/4x - 8 + 2/4x = 19 x = ___
2. Which expressions could complete this equation so that it has one solution?
4(4x - 3) - 6x = ___
Choose exactly two answers that are correct.
A.
12x - 12 - 2x
B.
9x - 12
C.
4x + 2 (3x - 6)
D.
4(2x + 3) - 24
3. David opens a bank account with $140 and then deposits $150 each month. Louis opens a bank account with $260 and deposits $120 each month. How many months will it take for David and Louis to have equal amounts of money in their accounts?
A.2
B.4
C.5
D.7
Answers
Answered by
3
x / 4 - 8 + 2 x /4 = 19
(1/4 + 2/4) x = 19 +8
(3/4 ) x = 27
x = 27 * 4/3 = 9 * 4 = 36
================
For the options A and C, we get 4(4x - 3) - 6x = 10 x -12
so we get 10x = 10 x this is true for any value of x.
But for B and D, we get 4(4x - 3) - 6x = 9x - 12 => x = 0
4(4x - 3) - 6x = 8 x - 12 => x = 0
there is one solution, x =0 for B and D.
====================
Difference between the balances in the two accounts at the beginning :
= $ 260 - $ 140 = $ 120
Difference in the deposit amount = $ 150 - $ 120 = $ 30
So the difference in balances reduces by $ 30 each month. So it will take $120/$30 = 4 months to even out.
Alternate method
============
Balance in David's account after x months = $ 140 + $ 150 * x
Balance in Louis acount after x months = $ 260 + $120 * x
$ 140 + $ 150 * x = $ 260 + $120 * x
$ (150 - $120) x = $260 - $ 140
30 * x = 120
x = 4
(1/4 + 2/4) x = 19 +8
(3/4 ) x = 27
x = 27 * 4/3 = 9 * 4 = 36
================
For the options A and C, we get 4(4x - 3) - 6x = 10 x -12
so we get 10x = 10 x this is true for any value of x.
But for B and D, we get 4(4x - 3) - 6x = 9x - 12 => x = 0
4(4x - 3) - 6x = 8 x - 12 => x = 0
there is one solution, x =0 for B and D.
====================
Difference between the balances in the two accounts at the beginning :
= $ 260 - $ 140 = $ 120
Difference in the deposit amount = $ 150 - $ 120 = $ 30
So the difference in balances reduces by $ 30 each month. So it will take $120/$30 = 4 months to even out.
Alternate method
============
Balance in David's account after x months = $ 140 + $ 150 * x
Balance in Louis acount after x months = $ 260 + $120 * x
$ 140 + $ 150 * x = $ 260 + $120 * x
$ (150 - $120) x = $260 - $ 140
30 * x = 120
x = 4
MasterChief:
Thanks alot.
Answered by
3
1.
1/4x - 8 + 2/4x = 19
1/4x + 2/4x = 19 + 8
Taking x as common
( 1/4 + 2/4) x = 27
(3/4) x = 27
x= 24 × 4/3
x= 9 × 4
x = 36
2.
4(4x - 3) - 6x =
For A option
4(4x - 3) - 6x = 12x - 12 - 2x
16x - 12 - 6x = 10x -12
10x -12 = 10x -12
For option B
4(4x - 3) - 6x = 9x - 12
16x -12 -6x = 9x -12
10x -12 =9x -12
x = 0.
For option C.
4(4x - 3) - 6x =4x + 2 (3x - 6)
10x - 12 = 4x + 6x - 12
10x -12 =10x - 12
For option D
4(4x - 3) - 6x =4(2x + 3) - 24
10x - 12 = 8x + 12 - 24
10x -8x = -12 + 12
2x= 0
x= 0.
Hence option A and C are correct.
3.
Difference between the balances Louis = $ 260 - $ 140 = $ 120
Difference in the deposit amount David = $ 150 - $ 120 = $ 30
The difference in balances reduces by $ 30 each month. So it will take $120/$30 = 4 months
Hence option B is correct.
1/4x - 8 + 2/4x = 19
1/4x + 2/4x = 19 + 8
Taking x as common
( 1/4 + 2/4) x = 27
(3/4) x = 27
x= 24 × 4/3
x= 9 × 4
x = 36
2.
4(4x - 3) - 6x =
For A option
4(4x - 3) - 6x = 12x - 12 - 2x
16x - 12 - 6x = 10x -12
10x -12 = 10x -12
For option B
4(4x - 3) - 6x = 9x - 12
16x -12 -6x = 9x -12
10x -12 =9x -12
x = 0.
For option C.
4(4x - 3) - 6x =4x + 2 (3x - 6)
10x - 12 = 4x + 6x - 12
10x -12 =10x - 12
For option D
4(4x - 3) - 6x =4(2x + 3) - 24
10x - 12 = 8x + 12 - 24
10x -8x = -12 + 12
2x= 0
x= 0.
Hence option A and C are correct.
3.
Difference between the balances Louis = $ 260 - $ 140 = $ 120
Difference in the deposit amount David = $ 150 - $ 120 = $ 30
The difference in balances reduces by $ 30 each month. So it will take $120/$30 = 4 months
Hence option B is correct.
Which equation models this situation?
Let s represent the number of small flowerpots she buys.
A.
5.6s + 2.4(s + 14) = 49.6
B.
(2.4 + 9.6)(14 – s) = 49.6
C.
2.4s + 5.6(14 – s) = 49.6
D.
5.6s + 2.8(14) = 49.6
Therefore total cost of small pots = 2.4s
Total number of pots bought is 14
So the number of large pots bought = 14-s
Hence the Total cost of large pots = 5.6(14-s)
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