Question

Some money was distributed equally among
some boys. Had there been 10 boys more
each boy would get 3 less. Had there
been 5 boys less each boy would get 2
more. Find the amount of money and the
number of boys present.​

Answer 1

Let the no. of boys be x

let the money distributed be y

hence the total money is xy

According to the given condition:-

(x+10)(y-3)=xy => 10y-3x=30 (i)

(x-5)(y+2) = xy => -5y+2x=10 (ii)

multiplying eqn (ii) by 2

-10y+4x=20 (iii)

adding (i) &(iii)

x=50

substituting the value of x in eqn (ii)

-5y+2(50)=10

-5y=10-100

-5y=-90

y=18

therefore the total money is equal to 900

hope this helps u mate

correct me if I am wrong