some of areas of two squares is 400 400 cm and difference of their Perry meter is 16 find the sides of the square
Answers
Answer:
answer is 25
Step-by-step explanation:
by dividing 400 upon 16
But not sure with this answer
Answer:
Side of first square= x = 16
Side of another square= y = 12
Step-by-step explanation:
Let side first square be x
the side of another square be y.
difference perimeter of two squares
4x-4y=16
4(x-y)=16
x-y=16/4
x-y=4
and x=4+y----- (1)
sum areas of two squares
x²+y²=400
Take (1) here
(4+y)²+y²=400
(4)²+(y)²+2×4×y+y²=400
16+y²+8y+y²=400
2y²+8y+16-400=0
2y²+8y-384=0
2(y²+4y-192)=0
we've taken 2 common and take at another side. then
y²+4y-192=0
Factorisation method
y²-12y+16y-192=0
y(y-12)+16(y-12)=0
(y+16) (y-12)=0
y+16=0
y= -16
y=12 because y being side cant be negative.
So, y=12
put y=12 in (1)
x=4+y
x=4+12
x=16
Side of first square= x = 16
Side of another square= y = 12