Some of the digits of a two digit number is 11 given number is less than the number obtained by the interchanging the digits by nine find the number
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let (10x+y) be the number, with x and y are two digits.
given x+y = 11
(10y+x) after interchanging digits
the both are differed by 9 given
so (10y + x ) - ( 10x + y) = 9
9y - 9x = 9
y-x =1
we have. x + y = 11 and y - x = 1
By solving we get
2y = 12
y = 6
x = 5
The numbers are 56 and 65
Any doubts, comment below ;;))
given x+y = 11
(10y+x) after interchanging digits
the both are differed by 9 given
so (10y + x ) - ( 10x + y) = 9
9y - 9x = 9
y-x =1
we have. x + y = 11 and y - x = 1
By solving we get
2y = 12
y = 6
x = 5
The numbers are 56 and 65
Any doubts, comment below ;;))
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