Question

some one help me out with this sum??​

Answer 1

Answer:

sorry l don't know about this topic

Answer 2

Answer:

A² - A + BC = $\left[\begin{array}{cc}12&12\\31&13\end{array}\right]$

Step-by-step explanation:

Given that,

A = $\left[\begin{array}{ccc}4&-2\\6&-3\end{array}\right]$ B = $\left[\begin{array}{ccc}0&2\\1&-1\end{array}\right]$ C = $\left[\begin{array}{cc}-2&3\\1&-1\end{array}\right]$

A² - A + BC = ?

Consider, A²

⇒ A² = A×A = $\left[\begin{array}{cc}4&-2\\6&-3\end{array}\right]$ $\left[\begin{array}{cc}4&-2\\6&-3\end{array}\right]$

⇒ A² = $\left[\begin{array}{cc}4(4)&-2(-2)\\6(6)&-3(-3)\end{array}\right]$

⇒ A² = $\left[\begin{array}{cc}16&4\\36&9\end{array}\right]$

Consider, BC

⇒ BC = $\left[\begin{array}{cc}0&2\\1&-1\end{array}\right] \left[\begin{array}{cc}-2&3\\1&-1\end{array}\right]$

⇒ BC = $\left[\begin{array}{cc}0(-2)&2(3)\\1(1)&-1(-1)\end{array}\right]$

⇒ BC = $\left[\begin{array}{cc}0&6\\1&1\end{array}\right]$

So, now

A² - A + BC = $\left[\begin{array}{cc}16&4\\36&9\end{array}\right] - \left[\begin{array}{cc}4&-2\\6&-3\end{array}\right] + \left[\begin{array}{cc}0&6\\1&1\end{array}\right]$

⇒ A² - A + BC = $\left[\begin{array}{cc}16-4&4-(-2)\\36-6&9-(-3)\end{array}\right] +\left[\begin{array}{cc}0&6\\1&1\end{array}\right]$

⇒ A² - A + BC = $\left[\begin{array}{cc}12&6\\30&12\end{array}\right] +\left[\begin{array}{cc}0&6\\1&1\end{array}\right]$

⇒ A² - A + BC = $\left[\begin{array}{cc}12+0&6+6\\30+1&12+1\end{array}\right]$

⇒ A² - A + BC = $\left[\begin{array}{cc}12&12\\31&13\end{array}\right]$

HOPE THIS WOULD BE HELPFUL FOR YOU