Question

Some organic molecule with a molar mass of 228 has an
empirical formula of C3H5O. What is the molecular
formula of this compound?

Answer 1

Explanation:

Molecular formula = n × Empirical formula

whereas n = (Molecular formula mass)/(Empirical formula mass) and Molecular formula mass is equal to Molar mass.

Empirical formula = C3H5O

Empirical formula mass = 3×12+5×1+1×16 = 57

n = 228/57 = 4

Molecular formula = 4 × (C3H5O) = C12H20O4

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