Some questions are given based on the below given pie graph. Study the pie graph and answer the questions with calculation in your notebook:
The contribution given by the students of Std. 7 for the celebration of Teacher's day is shown in the pie graph given below:
(1) In all how many rupees were collected as fund?
(2) How much contribution was given by Jafar?
(3) Calculate the degree measure of the contribution by Anuj and measure it in the figure.
(4) Who contributed the least fund?
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Amount of money contributed by :
Jafar : 18 rupees
Dev : 12 rupees
Matri : 30 rupees
Anuj : 36 rupees
Riya : 24 rupees
(1)Total collection of money = 18 + 12 + 30 + 24 + 36 = 120
(2) 18 rupees was contributed by Jafar.
(3) Degree of complete circle = 360°
Total money = 120 rupees
We get that : 120 rupees = 360°
Degree of each rupee = 360° / 120 = 3°
Money contributed by Anuj = 36 rupees
Measure of degree of his contribution = 36 * 3 = 108°
(4) Dev contributed to the least fund (18 rupees)
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Jafar : 18 rupees
Dev : 12 rupees
Matri : 30 rupees
Anuj : 36 rupees
Riya : 24 rupees
(1)Total collection of money = 18 + 12 + 30 + 24 + 36 = 120
(2) 18 rupees was contributed by Jafar.
(3) Degree of complete circle = 360°
Total money = 120 rupees
We get that : 120 rupees = 360°
Degree of each rupee = 360° / 120 = 3°
Money contributed by Anuj = 36 rupees
Measure of degree of his contribution = 36 * 3 = 108°
(4) Dev contributed to the least fund (18 rupees)
Hope this helps you dear!!
Plz mark my answer brainliest if you find it useful!!!!!
If you find any queries regarding this question plz reply me in the comments box!!!!
^_^
Answered by
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Solution :
i )
________________
Name | contribution
_______________
**Dev | Rs 12
________________
*Jafar | Rs 18
________________
**Riya | Rs 24
________________
**Anuj | Rs 36
________________
Matrix | Rs 30
________________
**Total | Rs 120
________________
Total fund collected = Rs 120
ii ) Jafar contribution = Rs 18
iii ) Degree measure of Anuj
Contribution = ( 36/360 ) × 120
= 120/10
= 12%
iv ) Least contributor is Dev.
•••••
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