Some students planned to go on a picnic and the total budget for food was ₹ 500 but in this 5 students were unable to go. As a result, the cost of food for each student increases to 10, then the total number of students is known.
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let total no. of students be = x
let cost of food for each student = x rs.
A.T.Q,
xy=500. -(1)
(x-5)(y+10)=500
(x-5)(500/x +10)=500
(x-5)(500+10x/x)=500
(x-5)(500+10x)=500x
500x - 2500 + 10x^2 - 50x = 500x
10x^2 - 50x - 2500 =0
10(x^2 - 5x - 250)=0
x^2 - 5x - 250 =0
solving the equation y will get the answer.. Hope it helps
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By direction options,
500/25 = 20, 500/20 = 25
By mathematical method, the main steps are :
xy=500 ...(i)
and (x−5)(y+5)=500
⇒x−y=5 or y=x−5
Puting in equation (i)
x(x−5)=500
⇒x^2−5x−500=0
⇒x=25 and attended =x−5=20
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