Question

Some tickets of ₹ 200 and some of ₹ 100, of a drama in a theatre were sold. The number of tickets of ₹ 200 sold was 20 more than the number of tickets of ₹ 100. The total amount received by the theatre by sale of tickets was ₹ 37000. Find the number of ₹ 100 tickets sold.

Answer 1

(x+20)200+x100=37000
(x+20)200+ x×100= 37000
200x+ 4000+ x ×100=37000
300x= 37000-4000
300x = 33000
x= 110

Number of tickets whose cost is 100= 110

Number of tickets whose cost is 200= 120

Answer 2

Answer:

The number of ₹ 100 tickets sold = 110

Step-by-step explanation:

Let x be no. of tickets were sold each cost $200.

Cost of x tickets = 200x

Let y be the no. of tickets sold each cost $100.

Cost of y tickets = 100y

Since we are given that The number of tickets of ₹ 200 sold was 20 more than the number of tickets of ₹ 100.

⇒ x = y+20 ----a

cost of 1 ticket is 200

The total amount received by the theatre by sale of tickets x and y  was ₹ 37000.

⇒200x+100y=37000 ---b

Now substituting the value of x from a in b

⇒200(y+20)+100y=37000

⇒200y+4000+100y=37000

⇒300y+4000=37000

⇒300y=37000-4000

⇒300y=33000

⇒$y=\frac{33000}{300}$

⇒y = 110

To find value of x put value of y in a

⇒x =y+20=110+20=130

Thus the number of ₹ 100 tickets sold = 110

The number of ₹ 200 tickets sold = 130