Math, asked by rohin111bhattacharya, 8 months ago

somebody please solve this question wrong answer will be reported ​

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Answered by mysticd
2

 \red{\frac{tan73 \degree + cot 61\degree }{tan17 \degree + cot 29\degree}}

 = \frac{tan73 \degree + cot (90-29)\degree }{tan(90-73)\degree + cot 29\degree}

 = \frac{tan73 \degree + tan 29\degree }{cot 73 \degree + cot 29\degree}

 = \frac{tan73 \degree + tan 29\degree }{\frac{1}{tan 73 \degree} + \frac{1}{tan 29\degree}}

 = \frac{\cancel{(tan73 \degree + tan 29\degree)} }{\frac{\cancel {(tan 29\degree + tan 73 \degree)}}{tan 73 \degree tan 29 \degree}}

= tan 73 \degree tan 29 \degree

 = tan 73 \degree tan (90 - 61) \degree

\green { = tan 73 \degree cot 61  \degree}

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Answered by anindyaadhikari13
2

Answer:

See this.

Step-by-step explanation:

I hope this will help you.

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