somebody pls help q25 the root I think shouldn't be negative
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RendemoShitiri:
is the answer is k=-4
no
its 9/4
wait.... I'll send you the answers
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when x= -4
f(x)=x2+px-4=0
now, (-4)2+p(-4)-4=0
16-4p-4=0
-4p=-12
p=3
putting the value of p in equation
x2+3x-4=0
Now comparing with ax2+bx+c=0
a=1, b=3, c=k
D=0
b2-4ac=0
(3)2-4×1×k=0
9-4k=0
-4k=-9
k=-9/-4
k=9/4
here the answer is
f(x)=x2+px-4=0
now, (-4)2+p(-4)-4=0
16-4p-4=0
-4p=-12
p=3
putting the value of p in equation
x2+3x-4=0
Now comparing with ax2+bx+c=0
a=1, b=3, c=k
D=0
b2-4ac=0
(3)2-4×1×k=0
9-4k=0
-4k=-9
k=-9/-4
k=9/4
here the answer is
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