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Answer 1

hey mate

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OD 16 cm

Also, sin 60°

- 26a)-

323 cm.

Area of the circle of radius 32 cm

2/3)

4 BC 32V3

22

-7683

1024

Let o be the centre of a circular table and ABC be the equilateral triangle

Then we draw ODL BC.

In ABD, we have: cos 60

OD

OB

OD

32

OBRadius 32 cm

BD

. BC 2BD

Area of the design (shaded region)

Area of equilateral AABC

X (32)

x32x 32-

x32x 32 x 3 c

22528

22 3

OB

BD

32

BD 163 cm