Question

Someone help class 9 prob quadrilaterals chapter, if you dont know pls ignore, take your time guys but pls give correct answer.

I will mark brainliest whoever gives proper answer​

Answer 1

Step-by-step explanation:

as the following figure is a square,

the diagonals intersect each other at 90°

angle PKQ =90°

and also T is the midpoint of PQ .

we can prove that triangle PKT us congruent to triangle KTQ

PT=PQ( T IS MIDPOINT)

KT=KT( COMMON SIDE)

PK=KQ( DIAGONALS OF SQUARE ARE EQUAL)

therefore, they are congruent by SSS congruence

by CPCT, anglePKT = angleKTQ

ANGLE PKT+ANGLE TKQ= ANGLE PKQ

LET anglePKT = angleKTQ BE x

x + x= 90°

2x=90°

x=45°

therefore ANGLE TKQ IS 45°

Answer 2

Answer:

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