Physics, asked by magnerchristin7480, 9 months ago

The radius of curvature of concave mirror is 24cm.object is placed at twice of focal length before mirror then find magnification

Answers

Answered by Anonymous
6

Answer:

Radius of curvature, R = -24cm

Focal length, f = - R/2 = - 24/2 = -12 cm

Object distance, u = 2 * f = 2 * (-12) = -24 cm

Let the image distance be denoted as “v” cm.

Using the mirror formula, we get

1/f = 1/v = 1/u

1/v = 1/f – 1/u

1/v = 1/(-12) – 1/(-24)

1/v = [-2 + 1] / 24

1/v = - 1/24

v = -24 cm

The magnification of the mirror is given as,

= - [v/u]

= - [(-24) / (-24)]

= - 1

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Answered by rishikeshgohil1569
3

Answer:

Radius of curvature, R = -24cm

Focal length, f = - R/2 = - 24/2 = -12 cm

Object distance, u = 2 * f = 2 * (-12) = -24 cm

Let the image distance be denoted as “v” cm.

Using the mirror formula, we get

1/f = 1/v = 1/u

1/v = 1/f – 1/u

1/v = 1/(-12) – 1/(-24)

1/v = [-2 + 1] / 24

1/v = - 1/24

v = -24 cm

The magnification of the mirror is given as,

= - [v/u]

= - [(-24) / (-24)]

= - 1

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PLZ FOLLOW ME

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