Physics, asked by magnerchristin7480, 11 months ago

The radius of curvature of concave mirror is 24cm.object is placed at twice of focal length before mirror then find magnification

Answers

Answered by Anonymous
6

Answer:

Radius of curvature, R = -24cm

Focal length, f = - R/2 = - 24/2 = -12 cm

Object distance, u = 2 * f = 2 * (-12) = -24 cm

Let the image distance be denoted as “v” cm.

Using the mirror formula, we get

1/f = 1/v = 1/u

1/v = 1/f – 1/u

1/v = 1/(-12) – 1/(-24)

1/v = [-2 + 1] / 24

1/v = - 1/24

v = -24 cm

The magnification of the mirror is given as,

= - [v/u]

= - [(-24) / (-24)]

= - 1

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Answered by rishikeshgohil1569
3

Answer:

Radius of curvature, R = -24cm

Focal length, f = - R/2 = - 24/2 = -12 cm

Object distance, u = 2 * f = 2 * (-12) = -24 cm

Let the image distance be denoted as “v” cm.

Using the mirror formula, we get

1/f = 1/v = 1/u

1/v = 1/f – 1/u

1/v = 1/(-12) – 1/(-24)

1/v = [-2 + 1] / 24

1/v = - 1/24

v = -24 cm

The magnification of the mirror is given as,

= - [v/u]

= - [(-24) / (-24)]

= - 1

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PLZ FOLLOW ME

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